Alcl3 H2O Naalo2 = Al(Oh)3 Nacl

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When we are met with a problem like this, it is always good khổng lồ start from counting the mol of each substances of the known mass.

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AlCl3 (relative mass of 133.34 g/mol) would be 0.136 mol while NaOH (r.m= 39.99 g/mol) would be 0.4 mol. From here, we can see that NaOH is the limiting reactant, which means there should be about 0.1 mol in the reaction. Therefore the recovered NaCl is 0.3 mol ~ 17.533 g. That if everything is made but the reaction only has a yield of 68%.

68% of 17.533 g is 11.92 g. Therefore the amount of sodium chloride retrieved would be 11.92 g from the reaction.


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When we are met with a problem lượt thích this, it is always good khổng lồ start from counting the mol of each substances of the known mass.

AlCl3 (relative mass of 133.34 g/mol) would be 0.136 mol while NaOH (r.m= 39.99 g/mol) would be 0.4 mol. From here, we can see that NaOH is the limiting reactant, which means there should be about 0.1 mol in the reaction. Therefore the recovered NaCl is 0.3 mol ~ 17.533 g. That if everything is made but the reaction only has a yield of 68%.

68% of 17.533 g is 11.92 g. Therefore the amount of sodium chloride retrieved would be 11.92 g from the reaction.

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When we are met with a problem like this, it is always good lớn start from counting the mol of each substances of the known mass.

AlCl3 (relative mass of 133.34 g/mol) would be 0.136 mol while NaOH (r.m= 39.99 g/mol) would be 0.4 mol. From here, we can see that NaOH is the limiting reactant, which means there should be about 0.1 mol in the reaction. Therefore the recovered NaCl is 0.3 mol ~ 17.533 g. That if everything is made but the reaction only has a yield of 68%.

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68% of 17.533 g is 11.92 g. Therefore the amount of sodium chloride retrieved would be 11.92 g from the reaction.


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Dynamic Periodic Table

Use the above periodic table khổng lồ determine the atomic mass of Sodium and Chlorine

Na= 22.99

Cl= 35.45

So you have 36/22.99 moles of sodium and 75.3/35.45 moles of chlorine

1.566 moles of Sodium

2.124 moles of Chlorine

to make sodium chloride one atom of sodium reacts with one atom of chlorine, so 1.566 moles of sodium will react with 1.566 moles of chlorine

with 2.124 - 1.566 moles of chlorine in excess or 0.558 moles

So all of the 1.566 moles or 36 grams of Sodium will react with 1.566*35.45 grams of chlorine or 55.515 giving you 91.51 grams of salt.

notice that I ignored the fact that chlorine is a diatomic molecule và just worked with the chlorine as atoms.


FollowFollowing

Dynamic Periodic Table

Use the above periodic table khổng lồ determine the atomic mass of Sodium and Chlorine

Na= 22.99

Cl= 35.45

So you have 36/22.99 moles of sodium và 75.3/35.45 moles of chlorine

1.566 moles of Sodium

2.124 moles of Chlorine

to make sodium chloride one atom of sodium reacts with one atom of chlorine, so 1.566 moles of sodium will react with 1.566 moles of chlorine

with 2.124 - 1.566 moles of chlorine in excess or 0.558 moles

So all of the 1.566 moles or 36 grams of Sodium will react with 1.566*35.45 grams of chlorine or 55.515 giving you 91.51 grams of salt.

notice that I ignored the fact that chlorine is a diatomic molecule & just worked with the chlorine as atoms.

More
Dynamic Periodic Table

Use the above periodic table to determine the atomic mass of Sodium & Chlorine

Na= 22.99

Cl= 35.45

So you have 36/22.99 moles of sodium và 75.3/35.45 moles of chlorine

1.566 moles of Sodium

2.124 moles of Chlorine

to make sodium chloride one atom of sodium reacts with one atom of chlorine, so 1.566 moles of sodium will react with 1.566 moles of chlorine

with 2.124 - 1.566 moles of chlorine in excess or 0.558 moles

So all of the 1.566 moles or 36 grams of Sodium will react with 1.566*35.45 grams of chlorine or 55.515 giving you 91.51 grams of salt.

notice that I ignored the fact that chlorine is a diatomic molecule và just worked with the chlorine as atoms.

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